If cosec2θ = 2 cosecθ - 1 . Then find the value of sinθ .

-1 2 0 1

1

cosec2θ = 2 cosecθ - 1  cosecθ = 2 -  \(\frac{1}{coseθ}\) cosecθ + \(\frac{1}{cosecθ}\) = 2 cosecθ = 1, then θ = 90° sinθ = sin90° = 1