CUET Preparation Today
The potential difference between the points A and C in the given circuit is:
|
2 V 3 V 5 V 7.5 V |
7.5 V |
The correct answer is Option (4) → 7.5 V
Now, Voltage across AD = 10 V $R_{eq}=4+2+2=8Ω$ [Connected in series] $∴I=\frac{V}{R}=\frac{10}{8}$ [By ohm's law] $V_{AC}=V_{AB}+V_{BC}$ $=4×\frac{10}{8}+2×\frac{10}{8}$ $=7.5V$ |
