The potential difference between the points A and C in the given circuit is:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 7.5 V
Now, Voltage across AD = 10 V
$R_{eq}=4+2+2=8Ω$ [Connected in series]
$∴I=\frac{V}{R}=\frac{10}{8}$ [By ohm's law]
$V_{AC}=V_{AB}+V_{BC}$
$=4×\frac{10}{8}+2×\frac{10}{8}$
$=7.5V$