Three brothers divided Rs.1890 among them in such a way that the share of the second is equal to \(\frac{5}{16}\) of the other two. Find the share of the second one.

450

                                  A + C    :          B

                Shares →      16       :           5

    Total amount = 1890

     16x + 5x = 1890

                x = \(\frac{1890}{21}\)

              5x = \(\frac{1890}{21}\) × 5 = 450