Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B2

Chapter

Calculus

Question:

If $y = 3e^{2x}+2e^{3x},$ then which one of the following is true ?

Options:

$\frac{d^2y}{dx^2}+5\frac{dy}{dx}+6y = 0 $

$\frac{d^2y}{dx^2}-5\frac{dy}{dx}+6y = 0 $

$\frac{d^2y}{dx^2}-5\frac{dy}{dx}-6y = 0 $

$\frac{d^2y}{dx^2}+5\frac{dy}{dx}-6y = 0 $

Correct Answer:

$\frac{d^2y}{dx^2}-5\frac{dy}{dx}+6y = 0 $