Practicing Success
Practicing Success
CUET Preparation Today
If $5 x-\frac{5}{x}+6=0$, then $x^2+\frac{1}{x^2}$ is: |
$\frac{86}{25}$ $\frac{43}{12}$ $\frac{81}{10}$ $\frac{86}{11}$ |
$\frac{86}{25}$ |
If $K-\frac{1}{K}=n$ then, $K^2+\frac{1}{K^2}$ = n2 + 2
$5[ x-\frac{1}{x}]=-6$ x - \(\frac{1}{x}\) = \(\frac{-6}{5}\) $x^2+\frac{1}{x^2}$ = (\(\frac{-6}{5}\))2 + 2 = \(\frac{36}{25}\) + 2 = $\frac{86}{25}$ |
