A certain number of students from school X appeared in an examination and 20% students failed. From school Y, 130% more students than that from school X, appeared in the same examination. If 90% of the total number of students appeared from from both the schools passed, then what is the percentage of students from school Y who failed (correct to one decimal place)?

5.65%

Let number of students in school X = 100

Number of failed  = 20% of 100

= 20

Passed students = 100 - 20 = 80

Number of students in school Y = 100 + 130% of 100 = 230

Total number of students in school X and school Y = 100 + 230 = 330

Number of passed students in both schools

=  \(\frac{9}{10}\)  × 330

= 297

So, number of passed students in school Y = 297 – 80

  = 217

According to question ,

Number of failed students in school Y = 230 –  217 = 13

Required percentage = \(\frac{13}{230}\) × 100% = 5.65%