A certain number of students from school X appeared in an examination and 20% students failed. From school Y, 130% more students than that from school X, appeared in the same examination. If 90% of the total number of students appeared from from both the schools passed, then what is the percentage of students from school Y who failed (correct to one decimal place)?
Answer & explanation
Correct answer: option 3
Let number of students in school X = 100
Number of failed = 20% of 100
= 20
Passed students = 100 - 20 = 80
Number of students in school Y = 100 + 130% of 100 = 230
Total number of students in school X and school Y = 100 + 230 = 330
Number of passed students in both schools
= \(\frac{9}{10}\) × 330
= 297
So, number of passed students in school Y = 297 – 80
= 217
According to question ,
Number of failed students in school Y = 230 – 217 = 13
Required percentage = \(\frac{13}{230}\) × 100% = 5.65%