Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Definite Integration

Question:

\(\int \limits_{\frac{1}{4}}^1 \frac{d x}{\sqrt{-x^2-2 x+3}}=\)

Options:

sin-1\((\frac{1}{4})\)

sin-1\((\frac{3}{4})\)

sin-1\((\frac{5}{8})\)

cos-1\((\frac{5}{8})\)

Correct Answer:

cos-1\((\frac{5}{8})\)

Explanation:

\(\int \limits_{\frac{1}{4}}^1 \frac{d x}{\sqrt{4-(x+1)^2}}⇒\begin{pmatrix}sin^{_1}\frac{x+1}{2}\end{pmatrix}_{\frac{1}{4}}^1⇒\frac{\pi}{2}-sin^{-1}(\frac{5}{8})\)

\(⇒cos^{-1}(\frac{5}{8})\)

Option D is correct.