Match List - I with List - II.

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Target Exam

CUET

Subject

-- Mathematics - Section B2

Chapter

Calculus

Question:

Match List - I with List - II.

List - I	List - II
(A) The minimum value of $f(x)=8 x^2-4 x+7$ is	(I) 48
(B) The maximum value of $f(x)=x+\frac{1}{x}, x<0$ is	(II) 13
(C) The maximum slope of the cure $y=-2 x^3+6 x^2+7 x+26$ is	(III) -2
(D) The minimum value of $f(x)=x^2+\frac{128}{x}$ is	(IV) $\frac{13}{2}$

Choose the correct answer from the options given below:

Options:

(A)-(I), (B)-(III), (C)-(II), (D)-(IV)

(A)-(IV), (B)-(III), (C)-(II), (D)-(I)

(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

(A)-(III), (B)-(IV), (C)-(II), (D)-(I)

Correct Answer:

(A)-(IV), (B)-(III), (C)-(II), (D)-(I)

Explanation:

The correct answer is Option (2) - (A)-(IV), (B)-(III), (C)-(II), (D)-(I)