Practicing Success
Let f(x) = discuss maxima and minima |
6 $n > 6$ 6 neither maxima and nor minima |
neither maxima and nor minima |
Here, f(x) = $f(a)= 6$ $f(1–h) = 6$ and $f(1+h) = 7 – (1+h) = 6 – h < 6$ Thus at $x = 1$ is neither a point of maxima nor minima |