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-- Mathematics - Section B1
Applications of Derivatives
Let f(x) = discuss maxima and minima
6
$n > 6$
neither maxima and nor minima
Here, f(x) =
$f(a)= 6$
$f(1–h) = 6$
and $f(1+h) = 7 – (1+h) = 6 – h < 6$
Thus at $x = 1$ is neither a point of maxima nor minima