For common emitter transistor amplifier the Audio Signal Voltage across the collector resistance of 2 kΩ is 2 V. Given that the current amplification factor of the transistor is 100, the base current is:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 10 μΑ
Using ohm's law, the collector current $(I_C)$ is -
$I_C=\frac{V_{RC}}{R_C}=\frac{2}{2000}=1mA$
The relationship between $I_C$ and base current $(I_B)$ is -
$I_C=βI_B$
$⇒I_B=\frac{I_C}{β}=\frac{1mA}{100}=0.01mA=10μΑ$