The correct answer is Option (3) → (B), (C), (D), (A)
Step 1: General principle
- The basicity of amines depends on the availability of the lone pair on nitrogen for protonation.
- Electron-donating groups (EDGs) increase basicity.
- Electron-withdrawing groups (EWGs) decrease basicity.
Step 2: Analyze each amine
- A: (CH₃)₂NH – aliphatic tertiary amine
- EDGs: two methyl groups → increase electron density on nitrogen → high basicity.
- B: p-Nitroaniline
- –NO₂ is a strong electron-withdrawing group → decreases lone pair availability → very low basicity.
- C: Aniline (–NH₂ attached to benzene)
- Lone pair on nitrogen delocalizes into benzene → reduces basicity → low basicity.
- D: p-Toluidine (p-CH₃–C₆H₄NH₂)
- –CH₃ is electron-donating → increases basicity slightly compared to aniline → moderate basicity.
Step 3: Arrange in increasing basicity
$B \,(\text{p-nitroaniline}) < C \,(\text{aniline}) < D \,(\text{p-toluidine}) < A \,(\text{dimethylamine})$
Answer: B < C < D < A |