The IUPAC name of the given compound is

The correct answer is Option (1) → 3-Bromo-4,4-dimethyl-cyclohexene

In naming a substituted cycloalkene, the ring with the double bond is the parent (cyclohexene). The double bond gets C-1 and C-2, and the numbering then runs in the direction that gives the substituents the lowest locants. The substituents are written in alphabetical order (the prefix di- is ignored).

In the given compound one carbon of the double bond is next to the carbon carrying Br, and that carbon is next to the carbon carrying the two methyl groups. Numbering from the double bond towards these groups:

• C-1 and C-2: the double bond

• C-3: the carbon carrying Br

• C-4: the carbon carrying both \( \ce{CH3} \) groups

This gives the locants {3, 4, 4}; numbering the other way would place them at 5, 5 and 6. With bromo before methyl alphabetically, the name is 3-bromo-4,4-dimethylcyclohexene.