If x - \(\frac{1}{x}\) = 39\(\sqrt{3}\)
then find the value of ( x + \(\frac{1}{x}\) )
Answer & explanation
Correct answer: option 2
⇒ If x - \(\frac{1}{x}\) = a then x + \(\frac{1}{x}\) = \(\sqrt {a^2 + 4}\)
Here,
x - \(\frac{1}{x}\) = 39\(\sqrt{3}\), then
⇒ x + \(\frac{1}{x}\) = \(\sqrt {(39\sqrt{3})^2 + 4}\) = 11