If x - \(\frac{1}{x}\) = 39\(\sqrt{3}\) then find the value of  ( x + \(\frac{1}{x}\) )

10 11 16 17

11

⇒ If x - \(\frac{1}{x}\) = a then x + \(\frac{1}{x}\) = \(\sqrt {a^2 + 4}\) Here, x - \(\frac{1}{x}\) = 39\(\sqrt{3}\), then  ⇒ x + \(\frac{1}{x}\) = \(\sqrt {(39\sqrt{3})^2 + 4}\) = 11