Find the value of (25)^3+(-29)^3+(4)^3

The correct answer is Option (1) → -8700

The identity if \(a+b+c=0\), then \(a^3+b^3+c^3=3abc\) turns three cubes into one product. Here \(a=25\), \(b=-29\), \(c=4\).

• \(a+b+c=25-29+4=0\), so the identity applies

• \(a^3+b^3+c^3=3\times25\times(-29)\times4\)

• \(=300\times(-29)=-8700\)

Tip: Whenever three cubes are added, first add the three numbers; if they total 0, the answer is \(3abc\), and the sign comes from the one negative number.