Practicing Success
The gravitational field in a region is given by $\vec{I}=(4 \hat{i}+\hat{j})$ N/kg. Work done by this field is zero when the particle is moved along the line |
y + 4x = 2 4y + x = 6 x + y = 5 all of the above |
y + 4x = 2 |
Work done will be zero when displacement is perpendicular to the filed. The field makes an angle $\theta_1=\tan ^{-1}\left(\frac{1}{4}\right)$ with positive x-axis While the line y + 4x = 2 makes an angle $\theta_2=\tan ^{-1}(-4)$ with positive x-axis $\theta_1+\theta_2=90^{\circ}$ i.e. the line y + 4x = 2 is perpendicular to $\vec{I}$ |