Practicing Success
An engine has an efficiency of 1/6. When the temperature of sink is reduced by 50°C, its efficiency is doubled. Temperature of the source is : |
27°C 99°C 62°C 124°C |
27°C |
Since efficiency of engine is : \(\eta = 1 - \frac{T_2}{T_1}\)= $\frac{1}{6} \Rightarrow \frac{T_2}{T_1}=\frac{5}{6}$ When the temperature of the sink is reduced by 50°C, its efficiency is doubled : \(2\eta = 1 - \frac{T_2-50}{T_1} = \frac{1}{3}\) $\Rightarrow \frac{T_2-50}{T_1} = \frac{2}{3} \Rightarrow \frac{T_2}{T_1} - \frac{50}{T_1} = \frac{2}{3}$ $\Rightarrow \frac{5}{6} - \frac{50}{T_1}= \frac{2}{3} \Rightarrow \frac{50}{T_1} = \frac{1}{6} $ $\Rightarrow T_1 = 300 = 27^oC $
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