The reaction between Cr2O72- and HNO3 in an acidic medium is
Cr2O72- + 5H+ + 3HNO2 → 2Cr3+ + 3NO3- + 4H2O
The rate of reaction is found to be 2.4 x 10-4 mol L-1 s-1, during the measured time interval. Find the rate of appearance of Cr3+ during the same time interval.
Answer & explanation
Correct answer: option 2
Rate = 2.4 x 10-4 mol L-1 s-1
+\(\frac{d[Cr^{3+}]}{dt}\) = 2 x (2.4 x 10-4) = 4.8 x 10-4 mol L-1 s-1