Practicing Success
INa box containing 100 bulbs, 10 are defective. What is the probability that out of a sample of 5 bulbs none is defective? |
$\left(\frac{9}{10}\right)^5$ $\frac{9}{10}$ $10^{-5}$ $\left(\frac{1}{2}\right)^2$ |
$\left(\frac{9}{10}\right)^5$ |
We have, p= Probability that a bulb is defective $= \frac{10}{100}=\frac{1}{10}$ $∴ q= 1 -p =\frac{9}{10}$ Let X be the number of defective bulbs in a sample of 5 bulbs. Then, X follows binomial distribution with n = 5, $p=\frac{1}{10}$ and $q= \frac{9}{10}$ such that $P(X =r)= {^5C}_r\left(\frac{1}{10}\right)^r\left(\frac{9}{10}\right)^{5-r}, r= 0, 1, ...,5$ ∴ Required probability $= P(X=0)$ $= {^5C}_0\left(\frac{1}{10}\right)^0\left(\frac{9}{10}\right)^{5}=\left(\frac{9}{10}\right)^{5}$ |