If $z = 3x + 4y$ be the objective function of a of a linear programming problem (LPP) and (3, 1), (2, 4), (0, 4), (5, 0) be corner points of the bounded feasible region. Then the maximum value of objective function is
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 22
$z = 3x + 4y$
At $(3,1)$ → $z = 3(3) + 4(1) = 13$
At $(2,4)$ → $z = 3(2) + 4(4) = 6 + 16 = 22$
At $(0,4)$ → $z = 3(0) + 4(4) = 16$
At $(5,0)$ → $z = 3(5) + 4(0) = 15$
Maximum value = 22 at (2, 4)