The magnetic moment in transition metals is calculated using the formula...........

$μ=\sqrt{n(n+2)}$

The correct answer is Option (1) → $μ=\sqrt{n(n+2)}$

The magnetic moment for transition metals (specifically those in the $3d$ series) is calculated using the spin-only formula:

$\mu = \sqrt{n(n + 2)}$

Where:

• $\mu$ is the magnetic moment in units of Bohr Magnetons (BM).
• $n$ is the number of unpaired electrons in the metal ion.