The electric field E associated with a progressive electromagnetic wave is given by $E = E_0\sin(kx-ωt)$. If $B_0$ is the amplitude of the magnetic field associated with the wave, then
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $\frac{E_0}{B_0}=\frac{ω}{k}$
Given: $E = E_0 \sin(kx - \omega t)$
For an electromagnetic wave, the relation between the amplitudes is
$\frac{E_0}{B_0} = c$
Also, $c = \frac{\omega}{k}$
⟹ $\frac{E_0}{B_0} = \frac{\omega}{k}$
Correct option: $\frac{E_0}{B_0} = \frac{\omega}{k}$