The electric field E associated with a progressive electromagnetic wave is given by $E = E_0\sin(kx-ωt)$. If $B_0$ is the amplitude of the magnetic field associated with the wave, then |
$\frac{E_0}{B_0}=\frac{ω}{k}$ $\frac{E_0}{B_0}=\frac{ω^2}{k^2}$ $\frac{E_0}{B_0}=\frac{k}{ω}$ $\frac{E_0}{B_0}=\frac{k^2}{ω^2}$ |
$\frac{E_0}{B_0}=\frac{ω}{k}$ |
The correct answer is Option (1) → $\frac{E_0}{B_0}=\frac{ω}{k}$ |