The electric field E associated with a progressive electromagnetic wave is given by $E = E_0\sin(kx-ωt)$. If $B_0$ is the amplitude of the magnetic field associated with the wave, then

$\frac{E_0}{B_0}=\frac{ω}{k}$

The correct answer is Option (1) → $\frac{E_0}{B_0}=\frac{ω}{k}$

Given: $E = E_0 \sin(kx - \omega t)$

For an electromagnetic wave, the relation between the amplitudes is

$\frac{E_0}{B_0} = c$

Also, $c = \frac{\omega}{k}$

⟹ $\frac{E_0}{B_0} = \frac{\omega}{k}$

Correct option: $\frac{E_0}{B_0} = \frac{\omega}{k}$