The reaction between 4-Bromobenzyl chloride with NaCN in ethanol leads to

4-Bromobenzyl cyanide 

The correct answer is option 2. 4-Bromobenzyl cyanide.

The reaction between 4-Bromobenzyl chloride with \(NaCN\) in ethanol is a nucleophilic substitution reaction (\(S_N2\) mechanism). Sodium cyanide \((NaCN)\) acts as the nucleophile and replaces the chlorine atom in the benzyl chloride group with a cyanide group \((CN)\).

When this compound reacts with \(NaCN\) in ethanol, the cyanide ion \((CN^-)\) attacks the carbon atom bonded to the chlorine, replacing the chlorine atom with a cyanide group. The product of this reaction is 4-Bromobenzyl cyanide.