If xy = 16 and $x^2 + y^2 = 32, $ then the value of (x + y) is :

±4 ±10 ±6 ±8

±8

If xy = 16 $x^2 + y^2 = 32, $ then the value of (x + y) is= ? Put the value of x and y = ±4 ( These values will satisfy the given equation.) (x + y) = (±4 + ±4) = ±8