If xy = 16 and x^2 + y^2 = 32, then the value of (x + y) is :

If xy = 16

$x^2 + y^2 = 32, $

then the value of (x + y) is= ?

Put the value of x and y = ±4 ( These values will satisfy the given equation.)

(x + y) = (±4 + ±4) = ±8