Answer & explanation
Correct answer: option 2
$ \text{Inductive reactance } X_L = \omega L = 2\pi fL = 400\times 1 \Omega = 400 \Omega$
$ R = 200\Omega$
$\text{Phase Angle } tan\phi = \frac{X_L}{R} = 2$
$\phi = 63^o$
Correct answer: option 2
$ \text{Inductive reactance } X_L = \omega L = 2\pi fL = 400\times 1 \Omega = 400 \Omega$
$ R = 200\Omega$
$\text{Phase Angle } tan\phi = \frac{X_L}{R} = 2$
$\phi = 63^o$