The mass number of helium is 4 and that of sulphur is 32. How many times the radius of sulphur nucleus is bigger than that of helium? |
8 4 2 $2 \sqrt{2}$ |
2 |
The correct answer is Option (3) → 2 The radius 'r' of a Nucleus - $r∝A^{1/3}$ $∴\frac{r_s}{r_{He}}=\left(\frac{32}{4}\right)^{1/3}=8^{1/3}=2$ |