If $R=\{(x,y)x,y∈z,x^2+y^2≤4\}$ is a relation in Z, then domain of R is:

{0, 1, 2} {0, -1, -2} {-2, -1, 0, 1, 2} None of these

{-2, -1, 0, 1, 2}

$∵R=\{(x,y)x,y∈z,x^2+y^2≤4\}$  $∴R=\{(-2,0),(-1,0),(-1,1),(0,-1),(0,1),(0,2),(0,-2),(1,0),(1,1),(2,0)\}$ Hence, domain of {-2, -1, 0, 1, 2}