Practicing Success
In ΔABC, DE || BC in such a way that A-D-B and A-E-C. If m ∠ACB = 40°, then m ∠DAE + m ∠ADE = _____. |
240° 120° 140° 230° |
140° |
Here, we have a triangle ABC in which DE is parallel to BC So, the \(\angle\)ACB = \(\angle\)AED = \({40}^\circ\) Now, consider the triangle ADE as we know that Sum of the angles of a triangle = 180 = \(\angle\)ADE + \(\angle\)DAE + \(\angle\)AED = 180 = \(\angle\)ADE + \(\angle\)DAE + 40 = 180 = \(\angle\)ADE + \(\angle\)DAE = \({140}^\circ\) Therefore, the required angle is \({140}^\circ\). |