Solve $\frac{2}{x}<3$

$(-∞,\frac{2}{3})∪(0,∞)$ $(-∞,0)∪(\frac{2}{3},∞)$ $(-∞,∞)∪(\frac{2}{3},∞)$ $(-∞,∞)$

$(-∞,0)∪(\frac{2}{3},∞)$

$\frac{2}{x}<3$ or $\frac{2}{x}-3<0$ (We cannot crossmultiply with x as x can be negative or positive) or $\frac{2-3x}{x}<0$ or $\frac{3x-2}{x}>0$ or $\frac{x-2/3}{x}>0$ Sign scheme of $\frac{x-2/3}{x}$ is as follows: $⇒x∈(-∞,0)∪(2/3,∞)$