The area of a rectangle whose length is 5 more than twice its width is 75 square unit. What is the perimeter of the rectangle?

40 units

The correct answer is Option (3) → 40 units

Let the width of the rectangle be x units.
Then its length is two times the width plus five, that is, 2x + 5.

Area of the rectangle = length × width
So, x(2x + 5) = 75

This gives 2x² + 5x − 75 = 0.
Solving, we get x = 5 (rejecting the negative value).

Width = 5 units
Length = 2 × 5 + 5 = 15 units

Perimeter = 2(length + width)
= 2(15 + 5)
= 40 units