Each resistor shown in figure has a resistance of 20 Ω and the battery has an emf of 12 V. The current supplied by the battery is

0.6 A

The correct answer is Option (2) → 0.6 A

Given: each resistor $R=20\ \Omega$, emf $E=12\ \text{V}$

The bridge is symmetric so no current flows through the central (bridge) resistor (ratios $20/20=20/20$) — central resistor can be ignored.

Left branch resistance $=R+R=20+20=40\ \Omega$, right branch resistance $=40\ \Omega$

Total equivalent resistance $R_{\text{eq}}=\left(\frac{1}{40}+\frac{1}{40}\right)^{-1}=20\ \Omega$

$I=\frac{E}{R_{\text{eq}}}=\frac{12}{20}=0.6\ \text{A}$

∴ Current supplied by the battery = 0.6 A