Match List-I with List-II
Choose the correct answer from the options given below: |
(A)-(IV), (B)-(I), (C)-(II), (D)-(III) (A)-(IV), (B)-(II), (C)-(III), (D)-(I) (A)-(IV), (B)-(III), (C)-(II), (D)-(I) (A)-(I), (B)-(II), (C)-(III), (D)-(IV) |
(A)-(IV), (B)-(I), (C)-(II), (D)-(III) |
The correct answer is Option (1) → (A)-(IV), (B)-(I), (C)-(II), (D)-(III)
(A) Angle between $\hat i-\hat j$ and $\hat i+\hat j$ Dot product: $(1,-1,0)\cdot(1,1,0)=1-1=0$ Angle $=\frac{\pi}{2}$ → (IV) (B) Angle between $\hat i-\hat j+\hat k$ and $-\hat i+\hat j-\hat k$ Dot product: $(1,-1,1)\cdot(-1,1,-1)=-1-1-1=-3$ Magnitudes $=\sqrt{3},\sqrt{3}$ $\cos\theta=\frac{-3}{3}=-1$ Angle $=\pi$ → (I) (C) Angle between $\hat i+\hat j$ and $-\hat i$ Dot product: $(1,1,0)\cdot(-1,0,0)=-1$ Magnitudes $=\sqrt{2},1$ $\cos\theta=\frac{-1}{\sqrt{2}}$ Angle $=\frac{3\pi}{4}$ → (II) (D) Angle between $\hat i+\hat k$ and $\hat k$ Dot product: $(1,0,1)\cdot(0,0,1)=1$ Magnitudes $=\sqrt{2},1$ $\cos\theta=\frac{1}{\sqrt{2}}$ Angle $=\frac{\pi}{4}$ → (III) Correct matching: A–IV, B–I, C–II, D–III |