Potential in the x-y plane is given as V

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Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

Potential in the x-y plane is given as V = 5(x² + xy) volts. The electric field at the point (1, −2) will be

Options:

3 J V/m

−5 J V/m

5 J V/m

−3 J V/m

Correct Answer:

−5 J V/m

Explanation:

$E_x=-\frac{\partial V}{\partial x}$ = -(10x + 5y) = -10 + 10 = 0

$E_y=-\frac{\partial V}{\partial x}$ = -5x = -5

∴ $\vec{E}$ = -5$\hat{j}$ V/m

∴ (B)