Potential in the x-y plane is given as V = 5(x2 + xy) volts. The electric field at the point (1, −2) will be
Answer & explanation
Correct answer: option 2
$E_x=-\frac{\partial V}{\partial x}$ = -(10x + 5y) = -10 + 10 = 0
$E_y=-\frac{\partial V}{\partial x}$ = -5x = -5
∴ $\vec{E}$ = -5$\hat{j}$ V/m
∴ (B)