The two possible nuclei to complete the reactions given below are, respectively (1) ${^{}_7N}^{14}+ {^{}_2He}^4 = {^{}_8O}^{17} +----$ |
${^{}_1 He}^4, {^{}_2H}^1$ ${^{}_1H}^1, {^{}_2He}^4$ ${^{}_2He}^2, {^{}_1H}^2$ ${^{}_4He}^2, {^{}_2H}^2$ |
${^{}_1H}^1, {^{}_2He}^4$ |
The correct answer is Option (2) → ${^{}_1H}^1, {^{}_2He}^4$ |