Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Inverse Trigonometric Functions

Question:

If $cos^{-1}\alpha + cos^{-1}\beta +cos^{-1}\gamma = 3\pi , $ then $\alpha ( \beta + \gamma ) + \beta (\gamma +\alpha ) + \gamma ( \alpha + \beta )$ equals :

Options:

0

1

6

12

Correct Answer:

6

Explanation:

The correct answer is option (3) → 6

$\cos^{-1}\alpha + \cos^{-1}\beta +\cos^{-1}\gamma = 3\pi$

⇒ iff $α=β=γ=-1$

so $α(β+γ)+β(γ+α)+γ(α+β)$

$=2+2+2=6$