A Zener diode is used in a voltage regulator circuit as shown below. Its breakdown voltage is 15 V. What is the current flowing through the zener diode?
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 5 mA
Current through the diode is zero because it is reversed biased.
Now,
$V=IR$ [Ohm's law]
$⇒I=\frac{V}{R_{net}}=\frac{25}{(1000+500)}=5mA$