If 8k^6 + 15k^3 - 2 = 0, then the positive value of ≤ft(k + 1/k) is:

8k⁶ + 15k³ – 2 = 0

Let, k³ = m

So, 8m² + 15m - 2 = 0

= 8m² + 16m - m - 2 = 0

= 8m (m + 2) - 1 (m + 2) = 0

= (8m - 1) (m + 2) = 0

= 8m - 1 = 0 

m = \(\frac{1}{8}\)

k³ = \(\frac{1}{8}\)

k =  \(\frac{1}{2}\)

$\left(k + \frac{1}{k}\right)$ = \(\frac{1}{2}\) + 2 = $2\frac{1}{2}$