A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is

82 kmph

Speed = \(\frac{ Distance}{ Time}\)

Let the speed of 2nd train be x 

So, according to the question

(50 + x) x \(\frac{5 }{18 }\) = \(\frac{\text{108 + 112}}{6}\)

(50 + x)  = \(\frac{\text{108 + 112}}{6}\) x \(\frac{18}{5}\)

(50 + x)  = \(\frac{\text{220}}{6}\) x \(\frac{18}{5}\)

50 + x = 132

x = 82 km/hr