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Find the remainder when we divide $ 3x^4 -2x^2 + 4x - 1 $ by $ 2x -1 $. |
2 3 $\frac{11}{16}$ $\frac{15}{16}$ |
$\frac{11}{16}$ |
When, 3x4 - 2x2 + 4x - 1 is divisible by 2x – 1 For finding the required remainder put 2x – 1 = 0 = x = 1/2 Now, the remainder is, = 3(1/2)4 - 2(1/2)2 + 4(1/2) - 1 = 3/16 - 1/2 + 2 -1 = 3/16 + 1/2 = 11/16 |
