If 1+sin θ=m cos θ, then what is the value of sin θ ?

$\frac{2 m^2-1}{m^2+1}$

$\frac{m^2-1}{m^2+1}$

$\frac{m^2+1}{2 m^2-1}$

$\frac{m^2+1}{m^2-1}$