for every $x∈B$

x is divisible by x ⇒ $(x,x)∈R$ (Reflexive)

$(x,y)∈R$

y is divisible by x ⇒ x is not divisible by y

$⇒(y,x)∉R$  (NOT symmetric)

$(x,y)∈R$ y is divisible by x

$(y,z)∈R$ z is divisible by y

⇒ z is divisible by x 

$⇒(x,z)∈R$ (transitive)