Practicing Success
Practicing Success
CUET Preparation Today
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for every $x∈B$ x is divisible by x ⇒ $(x,x)∈R$ (Reflexive) $(x,y)∈R$ y is divisible by x ⇒ x is not divisible by y $⇒(y,x)∉R$ (NOT symmetric) $(x,y)∈R$ y is divisible by x $(y,z)∈R$ z is divisible by y ⇒ z is divisible by x $⇒(x,z)∈R$ (transitive) |
