The LCM of \(\frac{1}{3}\), \(\frac{2}{9}\), \(\frac{5}{6}\) and \(\frac{4}{27}\) is?
Answer & explanation
Correct answer: option 3
Required number = \(\frac{LCM\;of\;Numerator}{HCF\;of\;Denominator}\)
= \(\frac{LCM\;of\;1, 2, 5, 4}{HCF\;of\;3, 9, 6, 27}\) = \(\frac{20}{3}\)