The function $f: Z→Z$ defined by $f(x)=x^2+x$ is, where Z is set of integer :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → many - one
$f(x)=x^2+x$
it is not onto as for $f(x)=1$ no x exists
for $x=-1,f(x)=0$
$x=0,f(x)=0$
⇒ it is Many - one