Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Mensuration: 3D

Question:

A solid sphere has a radius 8 cm. It is melted to form a cube, 20% is lost in this process. The cube is further melted to form a cone and 20% is again lost in the process. What is the radius (in cm) of cone?

Options:

32/√25

32/25

64/√9

64/5

Correct Answer:

32/25

Explanation:

Radius of sphere = R

Radius of cone = r

Volume of Sphere = \(\frac{4}{3}\) \(\pi \)R3

(Volume of cube is 80% of sphere  (since 20% is lost))

Volume of cube = \(\frac{4}{5}\) × \(\frac{4}{3}\) \(\pi \)R3

And volume of cone is further 80% of this; i.e. 

volume of cone = \(\frac{4}{5}\) × \(\frac{4}{5}\) × \(\frac{4}{3}\) \(\pi \)R3

⇒ \(\frac{1}{3}\) \(\pi \)r3 = \(\frac{4}{3}\) × \(\frac{4}{5}\) × \(\frac{4}{5}\) \(\pi \)R3

⇒ r3 =  \(\frac{(4)^3 R^3}{5^2}\)

⇒ r = \(\frac{4R}{\sqrt[3]{25}}\) = \(\frac{32}{\sqrt[3]{25}}\) cm