300 J of work is done in sliding a 2 kg block up an inclined plane of height 10 m. Taking g =10 m/s2, work done against friction is :
Answer & explanation
Correct answer: option 2
Work-Energy theorem : W = \(\Delta\) KE
\(\Delta\) KE = 0
300 – Wgravity – Wfriction = 0
Wgravity = mgh = 2m × 10m/s2 × 10m = 200 J
⇒ Wfriction = 100 J