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300 J of work is done in sliding a 2 kg block up an inclined plane of height 10 m. Taking g =10 m/s2, work done against friction is : |
50 J 100 J zero 150 J |
100 J |
Work-Energy theorem : W = \(\Delta\) KE \(\Delta\) KE = 0 300 – Wgravity – Wfriction = 0 Wgravity = mgh = 2m × 10m/s2 × 10m = 200 J ⇒ Wfriction = 100 J |
