If cotA =\(\frac{3}{4}\), then find the value of (10 sinA + 9 tanA)

14 16 18 20

20

cotA =\(\frac{3}{4}\)=\(\frac{3}{4}\)=\(\frac{B}{P}\)   [Triplet 3 , 4 , 5] H = 5 ⇒ 10 sinA + 9 tanA = 10 × \(\frac{4}{5}\) + 9 × \(\frac{4}{3}\) = 8 + 12 = 20