If (2x - 6)3 + (x - 8)3 + (x - 22)3 = (6x - 18) (x - 8) (x - 22), the…

Let, 2x - 6 = a, x - 8 = b and x - 22 = c

If, a³ + b³ + c³ = 3abc, then x + y + z = 0

Here, (2x - 6)³ + (x - 8)³ + (x - 22)³ = 3(2x - 6) (x - 8) (x - 22),

Therefore,

⇒ (2x - 6) + (x - 8) + (x - 22) = 0

⇒ 2x + x + x - 6 - 8 - 22 = 0

⇒ 4x = 36

⇒ x = 9

So, x² = 81