If (2x - 6)3 + (x - 8)3 + (x - 22)3 = (6x - 18) (x - 8) (x - 22), then find the value of x2

9 81 729 72

81

Let, 2x - 6 = a, x - 8 = b and x - 22 = c If, a3 + b3 + c3 = 3abc, then x + y + z = 0 Here, (2x - 6)3 + (x - 8)3 + (x - 22)3 = 3(2x - 6) (x - 8) (x - 22), Therefore, ⇒ (2x - 6) + (x - 8) + (x - 22) = 0 ⇒ 2x + x + x - 6 - 8 - 22 = 0 ⇒ 4x = 36 ⇒ x = 9 So, x2 = 81