Check the continuity of the given equation : f(x) = 2x + 3 at x = 1

discontinuous at x = 1 discontinuous at x = 1 but continuous at x = 2 continuous at x = 1 discontinuous at x = 2

continuous at x = 1

\(\lim_{x→1}\)= \(\lim_{x→1}\) (2x+3) = 2(1) + 3 = 5  \(\lim_{x→1}\) f(x) = 5 = f(1)   ∴ continous at 1