CUET Preparation Today
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a b c d |
c |
$\text{Maximum Intensity } I_{max} = (\sqrt I_1 + \sqrt I_2)^2 = (\sqrt I + 3\sqrt I)^2 = 16I$ $\text{Minimum Intensity } I_{min} = (\sqrt I_1 - \sqrt I_2)^2 = (3\sqrt I - \sqrt I)^2 = 4I$ $\frac{I_{max}}{I_{min}} = 4:1$ |
