If X, Y, Z, W & P are matrices of order 2 × n, 3 × k, 2 × p, n × 3 and p × k respectively. The restrictions on n, k & p so that PY + WY be defined are: |
k = 3, p = n k is arbitrary, p = 2 p is arbitrary, k = 3 k = 2, p = 3 |
k = 3, p = n |
The correct answer is Option (1) → k = 3, p = n $X_{2×n},Y_{3×k},Z_{2×p},W_{n×3},P_{p×k}$ So for PY to be defined $k=3$ for WY to be defined (3 = 3) So $P_{p×k}Y_{3×k}+W_{n×3}Y_{3×k}$ $(PY)_{p×k}+(WY)_{n×k}$ $p=n,k=3$ |