Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Matrices

Question:

If X, Y, Z, W & P are matrices of order 2 × n, 3 × k, 2 × p, n × 3 and p × k respectively. The restrictions on n, k & p so that PY + WY be defined are:

Options:

k = 3, p = n

k is arbitrary, p = 2

p is arbitrary, k = 3

k = 2, p = 3

Correct Answer:

k = 3, p = n

Explanation:

The correct answer is Option (1) → k = 3, p = n

$X_{2×n},Y_{3×k},Z_{2×p},W_{n×3},P_{p×k}$

So for PY to be defined

$k=3$

for WY to be defined

(3 = 3)

So $P_{p×k}Y_{3×k}+W_{n×3}Y_{3×k}$

$(PY)_{p×k}+(WY)_{n×k}$

$p=n,k=3$