In an examination, 40% of the students who appeared were boys and the rest were girls. The pass percentage of the boys was 60% and the overall pass percentage was 56%. What was the pass percentage of the girls?

$53\frac{1}{3}$

Let total number of students = 100x

Number of boys = 40% of 100x = 40x

Number of Girls = 100x - 40x = 60x

Number of passed boys = 60% of 40x = 24x

According to question ,

Total number of passed students = 56% of 100x = 56x

So , number of passed girls are = 56x - 24x = 32x

Percentage of pass girls = \(\frac{32x}{60x}\) × 100

= 53\(\frac{1}{3}\)